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The timer should then continue from zero on. I've looked at the documentation, and though I can see how I can link the two timers together, I don't see how I can make them top at an arbitrary bit value, or am I missing something? If there is no flag I can set which gives the the desired behavior, does anyone know an alternative solution? I would prefer a solution which requires as little CPU time as possible. The timer runs at 32MHz, the top value is not known before hand, and may be frequently modified.

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Please use the attached code snippets for an idea of implementing a 32bit Timer using two 16bit Timer module. Neverthless, it should be helpful for implementing your application. Generating a 32bit compare event is not stright forward. You have to write a single interrupt service routine for the two 16bit timer.

Based on the size of your compare value you have to decide which comparator interrupt to enable.

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If the Compare value is 0xXXXX then programming the lower 16bit timer for compare event is enough. If the Compare value is 0xXXXX then programming the higher 16bit timer for compare event is enough. In the ISR routine following this event the lower 16bit timer has to be enabled for a compare event.

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For 0xLLLL this may result in two lower matches instead of a high and low match. It would be helpful for implementing a solution for the above requirement.

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In my program I have to start two timers exactly at the same time. In my current code I start them behind one another just one line of code each but unfortunately the error with this method is too large. Timer4 is in OnePulse-Mode.

Draw a diagram illustrating the desired relationship the two signals. Since the second timer only operates when the first timer does, the light has to be on for at least part of the time the second timer is in an ON period. Sign up to join this community. The best answers are voted up and rise to the top. Home Questions Tags Users Unanswered. Day and night of the two timers Ask Question. Asked 3 years, 7 months ago. Active 2 years, 6 months ago. Viewed times.

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Does the requirement you imposed that "The timers may never simultaneously be at transitions in their schedules" mean that we are not supposed to let this condition ever occur? Real timers can sometimes turn themselves off that way, and certainly puzzle timers could, but this puzzle is challenging enough and the solution is better constrained without that possibility.

Perhaps the hints should be unhidden. Here's how we'd set the timers, and what would happen: Set timer A to be OFF during the hours: 1, 2, 13, 14 Set timer B to be OFF during the hours: 2,3,4,5,10,11,12,13,18,19,20,21 off four hours, on four hours, starting at This basically puts timer A on a 32 hour cycle, since it will become unpowered for four hours at 2am and 2pm every "day". Well worth retuning for even more light. Afterwards timer2 is set to off and timer1 will be on for 1 more hour since they aren't allowed to switch states at the same time Next timer1 will be off for 12 hours so timer2 won't move.

A larger-by-one D is possible with the same configuration by, heh, keeping one of the timers ON nonstop. A yet larger D is indeed possible with a different configuration. Thank you for understanding all the rules from an application of real timers, incidentally, not contrived and for playing by them. I do realise how the motor works now, so the impossibility proof is for posterity. If you reverse a timer or two, as in Third timer's a charm , more layouts are possible.

I think I've taken into account directionality now, have I made a wrong assumption? But its ability to keep itself on while the first timer is off can make a difference. And your analysis of diagram 1 nicely eliminates a puzzle I won't need to make now. If it is always on, the light is always on However, in order to advance into or proceed through to the "off" state, the plug must be powered. Sign up or log in Sign up using Google. Sign up using Facebook. Sign up using Email and Password.